9s^2+7s+1=0

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Solution for 9s^2+7s+1=0 equation: 



9s^2+7s+1=0

a = 9; b = 7; c = +1;
Δ = b2-4ac
Δ = 72-4·9·1
Δ = 13
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{13}}{2*9}=\frac{-7-\sqrt{13}}{18}
$


$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{13}}{2*9}=\frac{-7+\sqrt{13}}{18}
$

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